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solong [7]
4 years ago
8

What is the probability of rolling 2 on a die

Mathematics
2 answers:
Pavlova-9 [17]4 years ago
6 0

Answer:

1/6

Step-by-step explanation:

There are total of 6 numbers on a die, 1 through 6.

Getting 2 is one of the six possibilities.

Therefore, 1/6.

pantera1 [17]4 years ago
5 0

Answer:1/6

Step-by-step explanation:

Since there are six possible outcomes, the probability its any number over 6 (rolling on one will be 1/6 rolling on 2 will be 1/6 and so foward(the same thing for the rest going up to 6)

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The amount of money Tom has is 75% of Sallys amount of money. After Sally spent $120 and Tom saved all his money Tom's amount of
egoroff_w [7]

Answer: sally initially has $240, Tom initially has $180.

Step-by-step explanation:

Let initial amount of money sally has = x

Then, initial amount tom has = 75% * x = 0.75x

Now to present,

Amount sally has = x -120

Amount tom has = [x - 120] + [50% * (x-120)]

= x - 120 + 0.5x - 180

= 1.5x - 180

Since Tom didn't spend, it means this is the same amount tom has then we equate both equations.

0.75x = 1.5x - 180

180 = 0.75x

x = 240

Therefore, initial money of sally of sally = $240

Initial money of tom = 240 * 0.75 = $180.

6 0
3 years ago
A right cylinder has a radius of r inches and height of 2r inches.
lys-0071 [83]

Answer:

Part a) The lateral area is 4r^{2} \pi \ in^{2}

Part b) The area of the two bases together is 2r^{2} \pi\ in^{2}

Part c) The surface area is 6r^{2} \pi\ in^{2}

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

SA=LA+2B

where

LA is the lateral area

B is the area of the base of cylinder

we have

r=r\ in

h=2r\ in

Part a) Find the lateral area

The lateral area is equal to

LA=2\pi rh

substitute the values

LA=2\pi r(2r)

LA=4r^{2} \pi\ in^{2}

Part b) Find the area of the two bases together

The area of the  base B is equal to

B=r^{2} \pi\ in^{2}

so

the area of the two bases together is

2B=2r^{2} \pi\ in^{2}

Part c) Find the surface area of the cylinder

SA=LA+2B

we have

LA=4r^{2} \pi\ in^{2}

2B=2r^{2} \pi\ in^{2}

substitute

SA=4r^{2} \pi+2r^{2} \pi=6r^{2} \pi\ in^{2}

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Javier works in a photo lab and needs to make a reduced copy of a photograph that is 8 inches long. The customer wants the copy
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