<span>one of two or more alternative forms of a gene that arise by mutation and are found at the same place on a chromosome.</span>
Answer:
The genotypes found in the F2 offspring will be An1An1, An1An2 and An2An2.
Explanation:
In the example given in the question, the color of the petals of snapdragon flowers are given with the An1 allele having full activity and the An2 allele being the null allele. For the F1 offspring, two snapdragon flowers are crossed, one with red petals which is An1An1 and one with ivory petals which is An2An2. All the genotypes for the F1 offspring will result in An1An2.
Then using this F1 offspring, the F2 offspring is found and the genotype of the F2 offspring will be An1An1 / An1An2 / An1An2 / An2An2.
So the genotypes found in the F2 offspring will be An1An1, An1An2 and An2An2. One red petal snapdragon, 1 ivory snapdragon and 2 pink snapdragons.
I hope this answer helps.
Answer:
I think this should be the chart you were interested in...
Explanation:
Individual Shape in shaded
phenotype pedigrees
Male with gen. TT PTC taster square No
Male with gen. Tt PTC taster square No
Male with gen. tt Non-taster square Yes
Female with gen. TT PTC taster Circle No
Female with gen. Tt PTC taster Circle No
Female with gen. tt Non-taster Circle Yes
*gen- genotype
Answer:
25%
Explanation:
We have 2 independent genes with 2 alleles each: L/l and W/w
- W_: whiskers
- ww: no whiskers
- L_: long whiskers
- ll: short wiskers
Individuals with short whiskers will have the genotype <em>WWll </em>or <em>Wwll</em>.
<u>A cross between a rat heterozygous for both genes and a homozygous recessive rat is done:</u>
<h3>WwLl x wwll</h3>
-The homozygous rat will produce only <em>wl </em>gametes.
-The heterozygous rat will produce the following gametes: <em>WL</em>, <em>Wl</em>, <em>wL</em>, <em>wl</em>.
If you do a Punnett Square, you'll get that 25% of the offspring will be WwLl and will have short whiskers.