4 years ago

Select all tht apply

Mathematics

1 answer:

Zanzabum4 years ago

4 0

$n^{-2}= \cfrac{1}{16} \\ \\ \cfrac{1}{n^2} = \cfrac{1}{16}; \ \ \ n \neq 0 \\ \\ n^2=16 \\ \\ n=б \sqrt{16} \\ \\n=б4$

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<h2>Question 13 : x = 62°</h2>

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(: represents ratio or /)

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