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Gelneren [198K]
3 years ago
7

The altitude to the hypotenuse of a right triangle divides the hypotenuse into segments 3cm and 27cm long. Find the length of th

e altitude to the hypotenuse.

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0
To find the length of the altitude, we have to use the ratios of the similar sides.
Let the length of altitude=x
Ratio of sides:
\frac{x}{3} = \frac{27}{x}  \\
Cross \ multiply \\
 x^{2} =81 \\
Take \ square \ root.\\
 \sqrt{x^2}= \sqrt{81} \\
x=9 \\
So length of altitude is 9 cm.

Answer: 9 cm

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Can somone explain to me how to do this and help me thansk!!!
Gnesinka [82]
=> x² = (2.4)² + (4.8)²

=> x² = 5.76 + 23.04

=> x² = 28.8

=> x = 5.366563146

=> x = 5.4

Ans: 2nd option (5.4)

Hope this helps!
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3 years ago
If I have line segmants with the measurements 3in, 5 in and 8 in; can I make a triangle?​
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Answer:

Equilateral Triangle

Side a = 1

Side b = 1

Side c = 1

Angle ∠A = 60° = 1.0472 rad = π/3

Angle ∠B = 60° = 1.0472 rad = π/3

Angle ∠C = 60° = 1.0472 rad = π/3

C=60°B=60°A=60°b=1a=1c=1

Area = 0.43301

Perimeter p = 3

Semiperimeter s = 1.5

Height ha = 0.86603

Height hb = 0.86603

Height hc = 0.86603

Median ma = 0.86603

Median mb = 0.86603

Median mc = 0.86603

Inradius r = 0.28868

Circumradius R = 0.57735

Vertex coordinates: A[0, 0] B[1, 0] C[0.5, 0.86603]

Centroid: [0.5, 0.28868]

Inscribed Circle Center: [0.5, 0.28868]

Circumscribed Circle Center: [0.5, 0.28868]

Step-by-step explanation:

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4 years ago
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