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const2013 [10]
3 years ago
12

a 35 foot wire is secured from the top of a flagpole to a stake in the ground if the stake is 14 feet from the base of the flagp

ole how tall is the flagpole
Mathematics
1 answer:
zzz [600]3 years ago
3 0
If my calculations are correct the answer is 21 ft
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patriot [66]
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It costs 5 dollars per guest, so divide 35 by 5
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How do you simply the square root of 28
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3 0
3 years ago
55.27 is the same as 55 ____' 12".
choli [55]
<span><span>27100</span>(60)=<span>815</span>=16<span>15</span></span> The 16 is how many minutes you have. If you were not given the seconds, we would have to say that we have a remainder of (1/5) of a minute. Since 1 minute is (1/60), one-fifth of that is (1/300). Now we would need to see how many seconds that gives us. 1 second is (1/3600) of a degree, so we would need to divide (1/300) by (1/3600). Doing this gives us: <span><span><span>1300</span>÷<span>13600</span>=<span>1300</span>(3600)=12</span></span>
5 0
4 years ago
A projectile is shot into the air following the path,h(x) = - 5t2 + 20t + 3. At what time will it reach a maximum height? t = 1
kramer

Answer:

t = 2

Step-by-step explanation:

Notice that this expression for the projectile's path is that of a quadratic function with negative leading term. The graph of it therefore consists of a parabola with the branches pointing down (due to he negative leading coefficient). Therefore, the maximum of such parabola will reside at its vertex.

Recall that the formula for the position of the vertex in a general parabolic function of the form: y(x)=ax^2+bx+c, is given by the expression: x_{vertex}=-\frac{b}{2a}

In our case, the variable "x" is in fact "t", the leading coefficient (a) is -5, and the coefficient for the linear term (b) is 20.

Therefore, the maximum of the path will be when t=-\frac{20}{2(-5)} =\frac{20}{10} =2

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3 years ago
I need help on number 14
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