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2 years ago

Alex made a drawing of the path in his garden. What is the area of the path?

Mathematics

2 answers:

antoniya [11.8K]2 years ago

8 0

Answer:

$area = (7 \times 1) + (5 \times 1) + (8 \times 1) \\ = 7 + 5 + 8 \\ = 20 \: {m}^{2}$

Musya8 [376]2 years ago

3 0

Separate the pieces
(7x1) +(5x1)+(7x1)
7+5+7= 19
19m is your answer

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What is the common ratio of the sequence? -2,6,-18,54

aivan3 [116]

ANSWER

The common ratio is -3.

EXPLANATION

In general, the common ratio of a Geometric Sequence is given by:

$r = \frac{a_{n+1}}{a_{n}}$

We can find the common ratio using any two consecutive terms of the geometric sequence by dividing the subsequent term by the previous term.

The given sequence is -2,6,-18,54

Using the first two terms the common ratio is

$r = \frac{6}{ - 2} = - 3$

We could also used the second and third terms to get

$r = \frac{ - 18}{6} = - 3$

and so on and so forth.

Therefore the common ratio is -3.

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2 years ago

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Aleks04 [339]

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2 years ago

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If you are reading this please help!!!!

Soloha48 [4]

Given:

$1. -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$$

To find:

The product of the polynomials.

Solution:

1. $-3 x^{2}\left(4 x^{3}-7\right)$ $=-3 x^{2}(4 x^{3}) -3 x^{2}(-7)$

Multiply the numerical coefficient and add the powers of x.

$=-12 x^{5}+21 x^{2}$

2. $(6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=12 x^2+18x-10 x-15$

$=12 x^2+8x-15$

3. $(3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=3x^{3}+15 x^2-6x-x^{2}-5 x+2$

Add or subtract like terms together.

$=3x^{3}+14 x^2-11x+2$

The answer for multiplying polynomials:

$1. -12 x^{5}+21 x^{2}$

$2. \ 12 x^2+8x-15$

$3. \ 3x^{3}+14 x^2-11x+2$

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2 years ago

Choose the inequality that represents the following graph (ANSWER ASAPP PLEASE)

Makovka662 [10]

B - Since it is a dotted inequality, it would be a equal to and something else. And since it is greater than 3, it would be X is equal to or less than 3

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2 years ago

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Please show me how to solve the initial value problem y'=tanx y(pi/4)=3

AlexFokin [52]

The ODE is separable, i.e. you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx$

Integrating both sides gives the general solution.

$\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx$
$y=-\ln|\cos x|+C$

Given that $y\left(\dfrac\pi4\right)=3$ , we have

$3=-\ln\left|\cos\dfrac\pi4\right|+C$
$3=-\ln\dfrac1{\sqrt2}+C$
$3-\ln\sqrt2=C$

and so the particular solution to the IVP is

$y=-\ln|\cos x|+3-\ln\sqrt2$
$y=3-\ln|\sqrt2\cos x|$

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2 years ago