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3 years ago

Consider a sequence whose first five terms are: -3,0,3, 24, 81.

Mathematics

1 answer:

vfiekz [6]3 years ago

6 0

D is the correct answer

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What is the area of the trapezoid?

DiKsa [7]

The answer is actually choice B. To solve for the area of a trapezoid, you would do the formula a+b/2 h.

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3 years ago

Simplify.<br><br> n 6 · n 5 ÷ n 4 · n 3 ÷ n 2 · n

trasher [3.6K]

Answer: $n^{9}$

Step-by-step explanation:

Given expression: $n^6\cdot n^5\div n^4\cdot n^3\div n^2\cdot n$

The law of exponents are given by :_

$a^m\cdot a^n=a^{m+n}\\\\a^m\div a^n=a^{m-n}$

Using PEDMAS, first we solve division, we get

$n^6\cdot n^{5-4}\cdot n^{3-2}\cdot n\\\\=n^6\cdot n\cdot n\cdot n$

Now, using product law of exponent we get

$n^{6+1+1+1}\\\\=n^{9}$

7 0

3 years ago

Read 2 more answers

Im not sure if this is correct, pls help ! this test is timed !!

saw5 [17]

Answer:

im sorry but there is just a black screen

Step-by-step explanation:

3 0

3 years ago

In a fruit survey, children choose their favorite fruit out of apples, bananas and oranges. 29% chose oranges and 30% chose bana

Marizza181 [45]

30+29 = 59
percentages = 100 so 100-59 = 41
41%

4 0

3 years ago

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A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from

Nimfa-mama [501]

Step-by-step explanation:

Let

$m_p$ = mass of the painter

$m_s$ = mass of the scaffold

$m_e$ = mass of the equipment

$T$ = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

$3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)$

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of $m_e$ . The net torque on the scaffold is then

$T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0$

Solving for T,

$9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})$

$T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]$

$\:\:\:\:= 423.3\:\text{N}$

To solve for the the mass of the equipment $m_e$ , use the value for T into Eqn(1):

$m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}$

6 0

3 years ago