So the surface area is for the figure itself, and I just need to find the height. Please help!! (Geometry problem)
1 answer:
We need to cut it up and find the areas of each
ok so base=a^2
back sides are a^2 and a^2
total we have a^2+a^2+a^2=3a^2
we have now the 4 triangles, 2 of which are identical
the identical triangles are the side ones which are base a and height 1/2a
area of triangle=1/2bh
so the areas of them are 1/4a^2, times 2 since 2 of those triangles, 1/2a^2
add
3a^2+1/2a^2=7/4a^2
now the very top triangle and the cut corner triangle
very top is legnth a and base a so 1/2 a^2 is area
add
3 and 1/2a^2+1/2a^2=4a^2
we also need the small rectangles on side which is 1/2a times a times 2 since 2 of them=a^2 so a^2+4a^2=5a^2
now to find the corner bit in terms of a
use some imagination and lines to find legnths, right triangles and hypotonuse
the very top side is a√2 (45,45,90 angle/triangle)
we need to find slant height which is (a√6)/2
now
area=1/2bh
area=((a^2)√3)
add that
5a^2+(a^2)√3=250.5
find a
undistribute the a^2
(a^2)(5+√3)=501
use divide both sides by (5+√3)
a^2=501/(5+√3)
take squaer root of both sides
a= aprox 8.6267094364168 in
I hope this is right (should be, but alot done in head so maybe incorrect or off)
ok so base=a^2
back sides are a^2 and a^2
total we have a^2+a^2+a^2=3a^2
we have now the 4 triangles, 2 of which are identical
the identical triangles are the side ones which are base a and height 1/2a
area of triangle=1/2bh
so the areas of them are 1/4a^2, times 2 since 2 of those triangles, 1/2a^2
add
3a^2+1/2a^2=7/4a^2
now the very top triangle and the cut corner triangle
very top is legnth a and base a so 1/2 a^2 is area
add
3 and 1/2a^2+1/2a^2=4a^2
we also need the small rectangles on side which is 1/2a times a times 2 since 2 of them=a^2 so a^2+4a^2=5a^2
now to find the corner bit in terms of a
use some imagination and lines to find legnths, right triangles and hypotonuse
the very top side is a√2 (45,45,90 angle/triangle)
we need to find slant height which is (a√6)/2
now
area=1/2bh
area=((a^2)√3)
add that
5a^2+(a^2)√3=250.5
find a
undistribute the a^2
(a^2)(5+√3)=501
use divide both sides by (5+√3)
a^2=501/(5+√3)
take squaer root of both sides
a= aprox 8.6267094364168 in
I hope this is right (should be, but alot done in head so maybe incorrect or off)
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Consider the contrapositive of the statement you want to prove.
The contrapositive of the logical statement
<em>p</em> ⇒ <em>q</em>
is
¬<em>q</em> ⇒ ¬<em>p</em>
In this case, the contrapositive claims that
"If there are no scalars <em>α</em> and <em>β</em> such that <em>c</em> = <em>α</em><em>a</em> + <em>β</em><em>b</em>, then <em>a₁b₂</em> - <em>a₂b₁</em> = 0."
The first equation is captured by a system of linear equations,
or in matrix form,
If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be
and this is what we wanted to prove. QED
The test statistic z will be equal to -0.946 and it shows that there is no significant difference in the proportion of rehires between full time and part time.
Given sample sizes of 833 and 386 and result of samples 434 and 189.
Proportion of full time=434/833=0.52
Proportion of part time=189/386=0.49.
Difference in proportion =0.52-0.49
TTF- i∈ rho=0
TTF+i∈ rho≠0.
Mean of difference=0.03
Z=(X-μ)/σ
σ=
=0.0317
σ=0.0317
z=(0-0.03)/0.0317
=-0.03/0.0317
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p value will be =0.1736.
Because p value is greater than 0.01 so we will accept the null hypothesis which shows that there is no significant difference in the proportions.
Hence there is no significant difference in the proportion of rehires between full time and part time.
Learn more about z test at brainly.com/question/14453510
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