All categories

4 years ago

How do I simplify 6y-y

Mathematics

2 answers:

aniked [119]4 years ago

8 0

Think of 6y as

y + y + y + y + y + y

Now subtract a y from that.

y + y + y + y + y + y - y = y + y + y + y + y = 5y

Mama L [17]4 years ago

6 0

You have to take the Y out of the equation by factoring. y(6-1)

You might be interested in

Which volume is equivalent to 2.7 liters? A. 0.0027 milliliters B. 279 milliliters C. 2700 milliliters D. 27,000 milliliters

AURORKA [14]

Answer:The answer is 2700 millimeters

Step-by-step explanation:0.713 Us gallons = 2700 millimeters

4 0

4 years ago

Martin orders a pasta dish that is priced at $11.99. He also orders a drink. The total cost for the pasta and drink is $14.48. W

lyudmila [28]

Martin's drink equation = option b, 11.99 + d = 14.48

Nora's calzone equation = option a, c - 3 = 9.49

Hope this helps

8 0

3 years ago

Read 2 more answers

Helppppp meeeeeeee I need the answer

Vanyuwa [196]

Answer:

The answer is A

Explanation:

The short answer questions could be the x in,y=x+6.

The Points for each question on Diego's test has to add up to 100.

6 0

3 years ago

ABCD is a parallelogram. the diagram is not drawn to scale. if m angle CDA= 128 degrees, then m angle DAB= _____?

harina [27]

DAB must equal 52 because same side interior angles are supplementary. Supplementary describes 2 angles whose measures add up to 180

8 0

4 years ago

Read 2 more answers

State the null and alternative hypotheses to test if the population represented by Sample 1 has a mean that is 2.0 units higher

avanturin [10]

Answer:

Null Hypothesis, $H_0$ : $\mu_A-\mu_B$ = 2.0 units or $\mu_D$ = 2.0 units

Alternate Hypothesis, $H_A$ : $\mu_A-\mu_B\neq$ 2.0 units or $\mu_D\neq$ 2.0 units

Step-by-step explanation:

We are given the following data below and we have test if the population represented by Sample 1 has a mean that is 2.0 units higher than the population represented by Sample 2;

Pair : 1 2 3 4 5 6 7

Sample1 : 5 6 10 3 6 7 8

Sample2 : 4 4 3 5 5 5 3

Let $\mu_A$ = population mean represented by Sample 1

$\mu_B$ = population mean represented by Sample 2

$\mu_D$ = population mean matched-pair differences for Sample 1 - Sample 2

So, Null Hypothesis, $H_0$ : $\mu_A-\mu_B$ = 2.0 units or $\mu_D$ = 2.0 units

Alternate Hypothesis, $H_A$ : $\mu_A-\mu_B\neq$ 2.0 units or $\mu_D\neq$ 2.0 units

Here null hypothesis states that the population represented by Sample 1 has a mean that is 2.0 units higher than the population represented by Sample 2.

On the other hand, alternate hypothesis states that the population represented by Sample 1 has a mean that is not 2.0 units higher than the population represented by Sample 2.

6 0

4 years ago