3 years ago

Predict the offspring of a woman who carries but does not have the disorder and a man who does have the disorder

2 answers:

7 0

Assuming that the disorder is recessive, the phenotype for someone carrying the disorder would be Bb. Someone who doesn't have the disorder would be BB. Bb x BB = BB, BB, Bb, Bb. 50% would not have the disorder and 50% would be carriers.

Arisa [49]3 years ago

5 0

Its c 1 carrier female ; 1 normal male; 1 male with disorder

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