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Nutka1998 [239]

3 years ago

7

Quadrilateral EFGH is on a coordinate plane. Which statement is true?

1 answer:

Anton [14]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

Opposite sides are parallel in a parallelogram, so if they have different slope, the figure will not be a parallelogram.

_____

<em>Comments on other answer choices</em>

If the slope of diagonal EG is perpendicular to that of diagonal FH, it only proves the figure is some sort of kite. The figure may or may not be a parallelogram.

Adjacent sides being different lengths does not prove anything (except that the figure is not a rhombus).

Proving angle F is a right angle does not prove anything else about the shape of the figure. The figure may or may not be a parallelogram. (If it is a parallelogram, it is also a rectangle.)

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Question 4 Multiple Choice Worth 4 points)

natima [27]

Answer:

No solutions

Step-by-step explanation:

The slope is the same (3) The y-intercepts are different. Therefore, these are different parallel lines.

7 0

3 years ago

Select the postulate of equality or inequality that is illustrated.

Mademuasel [1]

Answer: Comparison Postulate

This is the idea that exactly one statement shown below is true

a > b

a = b

a < b

So if you compare two numbers, then either the left value is larger, the left is smaller, or the the left is the same as the value on the right.

4 0

2 years ago

A credit card customer owes $325.60.

Serjik [45]

Answer:

205.60

Step-by-step explanation:

325.60-120=205.60

The customer still owes 205.60

7 0

3 years ago

Read 2 more answers

Explain if you can please and thank you

svetlana [45]

<u>Given</u>:

Given that the angles of the kite.

The opposite angles of the kite measures (3y + 14)° and (y + 50)°

We need to determine the value of y.

<u>Value of y:</u>

We know the property that the opposite angles are equal.

Thus, applying the property, we have;

$3y+14=y+50$

Subtracting both sides of the equation by y, we have;

$2y+14=50$

Subtracting both sides of the equation by 14, we get;

$2y=36$

Dividing both sides of the equation by 2, we get;

$y=18$

Thus, the value of y is 18.

4 0

3 years ago

Let f(x) = -5e^(-x/3)<br><br> Find f^(6) (1)

Luba_88 [7]

Let's take the first derivative:

$f'(x) = (-5e^{-x/3})' = -5 \times (e^{-x/3})' = -5e^{-x/3} \times \left(-\dfrac{1}{3}\right) = \dfrac{5}{3}e^{-x/3}.$

Notice that we can write this as:

$f'(x) = -\dfrac{f(x)}{3}.$

By taking the derivative of both sides $n$ times, we get:

$f^{(n+1)}(x) = -\dfrac{f^{(n)}}{3}.$

This means that each time you take a derivative, a factor of $-\dfrac{1}{3}$ will appear. So we conclude that:

$f^{(n)}(x) = \left(-\dfrac{1}{3}\right)^nf(x).$

Taking $n=6$ and $x=1$ , we get:

$f^{(6)}(1) = \left(-\dfrac{1}{3}\right)^6 f(1) = \dfrac{-5e^{-1/3}}{729} = -\dfrac{5}{729}e^{-1/3}.$

So we finally get:

$\boxed{-\dfrac{5}{729}e^{-1/3}}.$

6 0

3 years ago