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3 years ago

Quadrilateral EFGH is on a coordinate plane. Which statement is true?

Mathematics

1 answer:

Anton [14]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

Opposite sides are parallel in a parallelogram, so if they have different slope, the figure will not be a parallelogram.

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<em>Comments on other answer choices</em>

If the slope of diagonal EG is perpendicular to that of diagonal FH, it only proves the figure is some sort of kite. The figure may or may not be a parallelogram.

Adjacent sides being different lengths does not prove anything (except that the figure is not a rhombus).

Proving angle F is a right angle does not prove anything else about the shape of the figure. The figure may or may not be a parallelogram. (If it is a parallelogram, it is also a rectangle.)

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Answer:

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Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

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$A=\pi r^{2}$

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$A=\pi r^{2}$

$36\pi=\pi r^{2}$

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$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

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Dvinal [7]

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