Question

The path of water from a hose on a fire tugboat can be approximated by the equation y=-0.0055x^2 +1.15x + 5, where y is the height above the ocean and x is the distance from the tugboat. When the water is 6 ft above the ocean how far is it from the tugboat

Answer 1

Answer:

The water is 208.22ft from the tug boat

Step-by-step explanation:

The governing equation is $y=-0.0055x^2 +1.15x + 5$

y is the height above the ocean

x is the distance from the tugboat

if y= 6ft, the equation will now become

$6=-0.0055x^2 +1.15x + 5$

we can arrange this properly to form a quadratic equation by grouping like terms.

$-0.0055x^2 +1.15x -1=0$

solving quadratically we have two values of x as  208.22ft and 0.873 ft.

We can take a more realistic value as a solution to our problems:

208.22ft