Is 17/100 greater or lesser than 8.7

The coordinates of the endpoints of ST are (-2,3) and (3, y) respectively supposethe distance between s and t us 13 units.What v

igor_vitrenko [27]

Answer:

The values of y would be -9 and 15

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$d=13\ units$

S(-2,3) and T(3,y)

substitute the given values in the formula and solve for y

$13=\sqrt{(y-3)^{2}+(3+2)^{2}}$

$13=\sqrt{(y-3)^{2}+25}$

squared both sides

$169=(y-3)^{2}+25$

$(y-3)^{2}=169-25$

$(y-3)^{2}=144$

take square root both sides

$y-3=(+/-)12$

$y=3(+/-)12$

$y=3(+)12=15$

$y=3(-)12=-9$

therefore

The values of y would be -9 and 15

5 0

4 years ago

The area of a square for on a scale drawing of 100 square centimeters and the scale drawing to 1 cm: 2 feet what is the area of

lilavasa [31]

Answer:

1. $\boxed{\text{400 ft}^{2}}$ ; 2. $\boxed{\frac{1}{3716}}$

Step-by-step explanation:

Step 1. Calculate the area of the floor

If the area A₁ of a square floor on the scale drawing is 100 cm², the length of a side is 10 cm.

The side length l of the actual floor is

l = 10 cm × (2 ft/1 cm) = 20 ft

The area A₂ of the floor is

A = l² = (20 ft)² = $\boxed{\text{400 ft}^{2}}\\$

Step 2. Calculate the area ratios

We must express both areas in the same units.

Let's express the area of the room in square centimetres.

l = 20 ft × (12 in/1 ft) = 240 in

l = 240 in × (2.54 cm/1 in) = 609.6 cm

A₂ = l² = (609.6 cm)² = 371 612 cm²

The area A₁ on the scale drawing is 100 cm².

The ratio of the areas is

$\frac{A_{1}}{ A_{2}} = \frac{100}{371612} = \frac{1 }{3716}\\$

The ratio of the area in the drawing to the actual area is $\boxed{\frac{1}{3716}}$

8 0

3 years ago

Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

Simplify,

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

$\frac{5(+-)\sqrt{25-8}}{4}$

$\frac{5(+-)\sqrt{17}}{4}$

Rewrite,

$\frac{5(+-)\sqrt{17}}{4}$

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

8 0

3 years ago

2.

Gekata [30.6K]

Answer:

A. A(n) = 150 • (0.74)^n–1 ; 33.29 cm

Step-by-step explanation:

This is a geometric sequence.

a%5B1%5D=1.5m=150cm, r=0.74

The formula is

a%5Bn%5D=a%5B1%5Dr%5E%28n-1%29

Just substitute a1 = 150cm and r = 0.74

a%5Bn%5D=150%280.74%29%5E%28n-1%29

That's the rule.

For the second part, substitute n = 6

cm.

7 0

3 years ago

24x + 30x = 3x + 24 + 4

Alinara [238K]

24x + 30x = 3x + 24 + 4

54x=3x+24+4

54x=3x+28

54x-3x=28

51x=28

X=28/51

7 0

3 years ago

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