Hello!
Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1.
A) x-axis, y=x, y-axis, x-axis
b) x-axis, y-axis, x-axis
c) y=x, x-axis, x-axis
d) y-axis, x-axis, y-axis, x-axis
The best answer is C180 rotation wud take that point to 4th quadrant
reflection in x-axis takes that to 1st quadrant
<span>reflection in y-axis brings it back to 2nd quadrant again. So, the sequence of transformations will bring A back to where it started
</span>
Hope this Helps! :)
Da number is n
2n-(n/2)≥12
times both sides by 2
4n-n≥24
3n≥24
divide both sides by 3
n≥8
Answer:
The answer is B.
Step-by-step explanation:
As you can see, box plot A is symmetrical so that applies to answers A and B. However, box B is very skewed to the right which makes it positively skewed so answer B is the only one that matches the correct description of the two box and whisker plots.
