Answer:
3. 3 : 5; 3: 5
Step-by-step explanation:
First, let's find the leght of the sides of each octagon.
![A= 18in^{2}](https://tex.z-dn.net/?f=A%3D%2018in%5E%7B2%7D)
The area of an octagon is defined by
![A=2(1+\sqrt{2})l^{2}](https://tex.z-dn.net/?f=A%3D2%281%2B%5Csqrt%7B2%7D%29l%5E%7B2%7D)
Replacing the area
![18=2(1+\sqrt{2})l^{2}\\\frac{18}{2(1+\sqrt{2})} =l^{2}\\l=\sqrt{\frac{18}{3.4} } \approx 2.3 \ in](https://tex.z-dn.net/?f=18%3D2%281%2B%5Csqrt%7B2%7D%29l%5E%7B2%7D%5C%5C%5Cfrac%7B18%7D%7B2%281%2B%5Csqrt%7B2%7D%29%7D%20%3Dl%5E%7B2%7D%5C%5Cl%3D%5Csqrt%7B%5Cfrac%7B18%7D%7B3.4%7D%20%7D%20%5Capprox%202.3%20%5C%20in)
Therefore, the side of the first octagon is 1.6 inches long.
Its perimeter is: ![P=8(2.3in)=18.4in](https://tex.z-dn.net/?f=P%3D8%282.3in%29%3D18.4in)
![A=50 in^{2}](https://tex.z-dn.net/?f=A%3D50%20in%5E%7B2%7D)
![50=2(1+\sqrt{2})l^{2}\\\frac{50}{2(1+\sqrt{2})} =l^{2}\\l=\sqrt{\frac{50}{3.4} } \approx 3.8 \ in](https://tex.z-dn.net/?f=50%3D2%281%2B%5Csqrt%7B2%7D%29l%5E%7B2%7D%5C%5C%5Cfrac%7B50%7D%7B2%281%2B%5Csqrt%7B2%7D%29%7D%20%3Dl%5E%7B2%7D%5C%5Cl%3D%5Csqrt%7B%5Cfrac%7B50%7D%7B3.4%7D%20%7D%20%5Capprox%203.8%20%5C%20in)
Therefore, the side of the second octagon is 3.8 inches long.
Its perimeter is
.
Now, let's divide to find each ratio:
(the ratio between sides).
(the ratio between perimeters).
Therefore, the closest ratio is 3. 3 : 5; 3: 5
<span>The fittable function seems to be 2 x^2+4 x+7.
So C (167)</span>
Answer:
7, 1/8th will be left after sun yi is done
Step-by-step explanation:
Answer:
the solutions to the equation 9x^2=4 is -2/3 and 2/3
Step-by-step explanation:
why are you reporting my answer when its correct
Answer: 364
Step-by-step explanation: