let's bear in mind that B is the midpoint and thus it cuts a segment into two equal halves.
![\bf \underset{\leftarrow \qquad \textit{\large 10x-6}\qquad \to }{\boxed{A}\stackrel{4x+2}{\rule[0.35em]{10em}{0.25pt}} B\stackrel{\underline{4x+2}}{\rule[0.35em]{10em}{0.25pt}\boxed{C}}} \\\\\\ AC=AB+BC\implies 10x-6=(4x+2)+(4x+2)\implies 10x-6=8x+4 \\\\\\ 2x-6=4\implies 2x=10\implies x=\cfrac{10}{2}\implies x= 5 \\\\[-0.35em] ~\dotfill\\\\ AC=(4x+2)+(4x+2)\implies AC=[4(5)+2]+[4(5)+2] \\\\\\ AC=22+22\implies AC=44](https://tex.z-dn.net/?f=%5Cbf%20%5Cunderset%7B%5Cleftarrow%20%5Cqquad%20%5Ctextit%7B%5Clarge%2010x-6%7D%5Cqquad%20%5Cto%20%7D%7B%5Cboxed%7BA%7D%5Cstackrel%7B4x%2B2%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20B%5Cstackrel%7B%5Cunderline%7B4x%2B2%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BC%7D%7D%7D%20%5C%5C%5C%5C%5C%5C%20AC%3DAB%2BBC%5Cimplies%2010x-6%3D%284x%2B2%29%2B%284x%2B2%29%5Cimplies%2010x-6%3D8x%2B4%20%5C%5C%5C%5C%5C%5C%202x-6%3D4%5Cimplies%202x%3D10%5Cimplies%20x%3D%5Ccfrac%7B10%7D%7B2%7D%5Cimplies%20x%3D%205%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20AC%3D%284x%2B2%29%2B%284x%2B2%29%5Cimplies%20AC%3D%5B4%285%29%2B2%5D%2B%5B4%285%29%2B2%5D%20%5C%5C%5C%5C%5C%5C%20AC%3D22%2B22%5Cimplies%20AC%3D44)
Answer:
1.3
Friend is wrong
Step-by-step explanation:
Given:
friend's claim: height of his building is more than 1.50 times the height of yours
line of sight to the top edge of the other building makes an angle of 21° above the horizontal
line of sight to the base of the other building makes an angle of 52° below the horizontal
Solution:
Let A be the height of your building is A
Let B+A his building is B higher than yours.
Let the distance between the buildings is x.
then
tan 52 = A/x
tan 21 = B/x
A/B = tan 52 / tan 21
= 1.27994 / 0.38386
A/B = 3.33
(A + B) / A = 1.5
0
A/A + B/A = 1.50
1 + B/A = 1.50
B/A is basically (B/x) / (A/x)
So
1+ 3.33 / 3.33
= 4.33/3.33
= 1.3
Since 1.3 is not equal to 1.5
Hence the friend's claim is wrong.
Answer:
is 20 is your answer I believe
1yd=3ft...so 39ft=(39/3)=13yds
1mins =60seconds
13/60=0.22yds/secs
If 3z=2z+5 and z=5, then you’d just plug the 5 in.
3(5)=2(5)+5 —> 15=10+5 —> 15=15
This statement is TRUE because 15 does equal 15.
I hope this helps. :)
