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Alexeev081 [22]
3 years ago
14

If f(x)=x^3/2 then f'(4)=

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0
First you have to find the derivative of the equation f(x)=x^{3/2} . To do this, you can use the power rule (f(x)= x^{n} goes to f'(x)=nx^{n-1}). so the derivative would be f'(x)= \frac{3}{2} x^{ \frac{3}{2}-1 } , which can be written as f'(x)= \frac{ 3\sqrt{x}}{2}. then you plug in 4 for x, and get \frac{3 \sqrt{4} }{2} =3, so f'(x)=3
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Answer:

Step-by-step explanation:

Discussion

The object of this is make w by itself on one side of the equation.

Equation

x = 3 (y + w) - 1               Add 1 to both sides of the equation.

x + 1 = 3(y + w) - 1 + 1      Combine

x + 1 = 3(y + w)                 Remove the Brackets

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x + 1 - 3y = 3y-3y + 3w   Combine

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(x + 1)/3 = w

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