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3 years ago

$5000 principal earning 5% compound annually after 4 years

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

5000(1 + 0.05)^4 = $6077.53

PSYCHO15rus [73]3 years ago

3 0

Amount after 5 years = 5000(1 + 0.05)^4 = $6077.53

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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

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Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

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