Can u show the whole question
Answer:
50 tickets with a meal and 20 tickets without a meal
Step-by-step explanation:
Create two equations. Group the information based on labels. All the amounts that have $ in it go with one equation and the number of tickets will be in the second equation.
I will let x represent with a meal and y will represent without a meal
35x + 25y = 2250
x + y = 70
I will solve using substitution, so I will solve for y in the second equation. To do this, I will subtract x from both sides.
x - x + y = 70 - x
y = 70 - x
Now I will substitute in for y in the first equation and solve for x.
35x + 25(70 - x) = 2250
35x + 1750 - 25x = 2250
10x + 1750 = 2250
10x + 1750 - 1750 = 2250 - 1750
10x = 500
10x/10 = 500/10
x = 50
Now I will solve for y. I will use the original second equation and substitute 50 in for x.
x + y = 70
50 + y = 70
50 - 50 + y = 70 -50
y = 20
50 tickets with a meal and 20 tickets without a meal
<span>The power of a number says how many times to use the number in a multiplication. It is written as a small number to the right and above the base number.</span>
Just multiply or divide both terms by any number.
For example, multiply each term by 2 to get 36x+18y.
Or, divide each term by 3 to get 6x+3y.
Please consider marking this answer as Brainliest to help me advance.
I think:
a+a+2a+2a=180
6a=180
a=30
3x-12=x
2x=12
x=6
8-y=x
8-y=6
y=2
