So Maurice would have 2N nickels
Total number of coins is N + 2N + 9 = 3N + 9
Each nickel is 5 pennies
3N of nickels = 15N pennies
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Their worth is 84 cents
15N + 9 = 84
15N = 75
N = 75/15 = 5
N = 5
This means Nina has 5 nickels.
for the 0 u put zero the for 5 u put 40 then for 10 u put 80 then for 15 u put 120 then for 20 u put 160
To find the specification limit such that only 0.5% of the bulbs will not exceed this limit we proceed as follows;
From the z-table, a z-score of -2.57 cuts off 0.005 in the left tail; given the formula for z-score
(x-μ)/σ
we shall have:
(x-5000)/50=-2.57
solving for x we get:
x-5000=-128.5
x=-128.5+5000
x=4871.50
Answer:
8s-8
Step-by-step explanation:
Use the distributive property: #(a-b) = #*a - #*b. In this case 8s - 8.
Hope it helps!
