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Mandarinka [93]
3 years ago
9

4) How many cards must you draw from a deck of 52 cards to have at least 5 cards of one suit?

Mathematics
1 answer:
malfutka [58]3 years ago
4 0
<h3>Answer: 17 cards</h3>

================================================

Explanation:

The best case scenario is that you pull 5 cards from the same suit in a row (eg: 5 spades in a row).  However, we have to plan for the worst case scenario that way we can guarantee to have 5 cards in one suit without having to look at the cards.

The worst case scenario is that you pull cards such that you get one suit at a time (eg: spade, heart, club, diamond). On the 5th draw, we finally get a card that repeats a suit.

If we repeat the sequence {spade, heart, club, diamond} in that order a total of two times, then we'll have 8 cards with 2 cards per suit.

Doing that sequence four times we'll have 4*4 = 16 cards and 4 cards per suit. That 17th card will repeat a suit a fifth time and this is when we'll be guaranteed to have at least 5 cards of one suit.

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Answer:

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Cost of two tickets = 2 * 30 = £60

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Money spent on dinner = (1/3)*x

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Remaining \ money =x -  \dfrac{1}{3}x =\dfrac{3}{3}x-\dfrac{1}{3}x=\dfrac{2}{3}x

Money \ spent \ on \ dessert = \dfrac{1}{4} *\dfrac{2}{3}x =\dfrac{1}{6}x\\\\\\

Total money - money spent on dinner - money spent on dessert = 60

x -\dfrac{1}{3}x -\dfrac{1}{6}x=60\\\\\\\dfrac{6}{6}x-\dfrac{1*2}{3*2}-\dfrac{1}{6}x =60\\\\\\\dfrac{6}{6}x-\dfrac{2}{6}x-\dfrac{1}{6}x=60\\\\\\\dfrac{6-2-1}{12}x=60\\\\\\\dfrac{3}{12}x=60\\\\\\x=60*\dfrac{12}{3}=60*4=240

Money that Puvi had at the start of the night = £ 240

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2 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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