a. We assume you want the dot product. That is the sum of the products of the corresponding components.
... V1•V2 = (-6)(-3) + (4)(6) = 18 + 24 = 42
b. V1•V2 = |V1|·|V2|·cos(α)
... α = arccos(V1•V2/(|V1|·|V2|)
... α = arccos(42/√(((-6)²+4²)((-3)²+6²)))
... α = arccos(42/√2340)
... α ≈ 29.74°
c. The scalar projection of V1 onto V2 is the dot product of V1 with the unit vector in the V2 direction.
... V1•V2/|V2| = 42/√45 = 42/(3√5) = (14/5)√5
d. The projection of V1 onto V2 is the result of part c multiplied by the unit vector in the direction of V2.
... projection of V1 onto V2 = (14/5)√5·(-3, 6)/(3√5) = (14/5)(-1, 2) = (-14/5, 28/5)
Answer:SAS
Step-by-step explanation:
the SAD ( or side-angle -side ) postulate basically states that if two sides of of two triangles ana the included angle are congruent , the two triangles are in fact congruent ( if that makes sense)
Answer:
52°
Step-by-step explanation:
(I'm assuming lines JK and HI are parallel)
∠JKA and ∠HIA are corresponding so they are congruent.
Therefore, since ∠JKA is 62, so is ∠HIA. Then knowing the sum of interior angles of a triangle always must be 180, you can just do the math to get 52° as the remaining angle.
66° + 62° + ∠x = 180
∠x = 52°
Answer:
B and C only show direct proportion
Answer:
137 boxes
Step-by-step explanation:
1096 boxes * 0.125(12.5% of boxes weighing less than a pound) = 137 boxes
