Are you looking for the length from E to F?
Given that Joseph has 24 cousins, and he has 6 more females than males, the number of females will be obtained as follows;
suppose he had x males, number of females will be x+6.
The total will be:
x+(x+6)=24
x+x+6=24
2x+6=24
2x=24-6
2x=18
x=18/2
x=9
thus the number of male cousins is 9, the number of female cousins will be 9+6=15
We therefore conclude that he has 9 male cousins and 15 female cousins
There are 
ways of drawing a 4-card hand, where
is the so-called binomial coefficient.
There are 13 different card values, of which we want the hand to represent 4 values, so there are 
ways of meeting this requirement.
For each card value, there are 4 choices of suit, of which we only pick 1, so there are 
ways of picking a card of any given value. We draw 4 cards from the deck, so there are 
possible hands in which each card has a different value.
Then there are 
total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is
Sorry I'm too dumb to figure out the answer, I hope you find help soon.
