Step-by-step explanation:
we don't see the complex numbers.
so, we cannot check their distances.
a suspicion, though.
sqrt(45) a distance between 2 complex numbers is
sqrt(a² + b²).
so,
a² + b² = 45
a nice combination of whole square numbers would be 6 and 3.
6² + 3² = 36 + 9 = 45
if that is the case, then that would mean one of the following committed numbers
6 + 3i
3 + 6i
-6 + 3i
6 - 3i
-6 - 3i
-3 + 6i
3 - 6i
-3 - 6i
one of these numbers must be the result of the subtraction of the 2 provided complex numbers.
remember
(a + bi) - (c + di) = a-c + (b-d)i
It would be 6 in. Because if you separate 60 into two parts such that one part will exceed the other part by 36
36a+16b. The greatest common factor is 4
= 4(9a+4b)
Answer:
D I'm not sure if it is correct but I'm sorry if wrong Good luck!
take 13cm and times it by four
i think
