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umka21 [38]
3 years ago
12

Match each sequence to its appropriate recursively defined function

Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

  • f(1) = -24; f(n) = 4·f(n-1)
  • f(1) = 13; f(n) = f(n-1) + 26
  • f(1) = 28; f(n) = -4·f(n-1)

Step-by-step explanation:

Identify the first term of the sequence. First terms are -24, 13, 28. Find the matching f(1). There are two choices for each first term.

Then determine the relation of each term to the previous term. In two of the sequences, a factor of 4 is involved. For the sequence starting with -24, the adjacent terms have the same sign, so the factor is +4. For the sequence starting with 28, adjacent terms have alternating signs, so the factor is -4.

For the sequence starting with 13, the second term is 3 times the first, but it is also 26 added to the first. You have to look at the next term to see if the sequence is geometric with a ratio of 3, or arithmetic with a difference of 26. The latter is the case, so the recursive definition will involve addition, not multiplication.

The recursively defined functions are shown above in the order of the given sequences.

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F(x)=x⁴-1
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Newton’s Method: x[n+1]=x[n]-f(x[n])/f'(x[n]); x[n+1]=x[n]-(x[n]⁴-1)/4x[n]³
x₁=3.00390625
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vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}

we have

a=32\ units

b=27\ units

B=37\°

step 1

Find the measure of angle A

\frac{a}{sin(A)}=\frac{b}{Sin(B)}

substitute the values

\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}

sin(A)=(32)Sin(37\°)/27=0.71326

A=arcsin(0.71326)=45.5\°

The measure of angle A could have two measures

the first measure-------> A=45.5\°

the second measure -----> A=180\°-45.5\°=134.5\°

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to  180\°

A+B+C=180\°

substitute the values

A=45.5\°

B=37\°

45.5\°+37\°+C=180\°

C=180\°-(45.5\°+37\°)=97.5\°

step 3

Find the first length of side c

\frac{a}{sin(A)}=\frac{c}{Sin(C)}

substitute the values

\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}

c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units

therefore

the measures for the first solution of the triangle are

A=45.5\° , a=32\ units

B=37\° , b=27\ units

C=97.5\° , b=52.7\ units

step 4    

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to  180\°

A+B+C=180\°

substitute the values

A=134.5\°

B=37\°

134.5\°+37\°+C=180\°

C=180\°-(134.5\°+37\°)=8.5\°

step 5

Find the second length of side c

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substitute the values

\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}

c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units

therefore

the measures for the second solution of the triangle are

A=45.5\° , a=32\ units

B=37\° , b=27\ units

C=8.5\° , b=7.9\ units

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