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Tom [10]
3 years ago
8

Which relation is a function?

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Look for the case in which every input is unique (no repetitions).

A does not qualify, as 3 appears as an input twice.

B does not qualify, for the same reason

C qualifies (is a function), because all the inputs {1, 2, 3, 4} are unique.

D does not qualify (see A, above).

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PLEASE HELP I AM STUCK ON THIS
Fofino [41]

Answer:

Step-by-step explanation:

This is a right triangle problem.  The reference angle is x, the side opposite the reference angle is 32, and the hypotenuse is 58.  The trig ratio that relates the side opposite a reference angle to the hypotenuse is the sin.  Filling in accordingly:

sin(x)=\frac{32}{58}

Because you are looking for a missing angle, you will use your 2nd button and then the sin button to see on your display:

sin^{-1}(

Within the parenthesis enter the 32/58 and you'll get your angle measure.  Make sure your calculator is in degree mode, not radian mode!!!

4 0
3 years ago
Which of the following has a solution set of {x | x = 0}?
notka56 [123]

Answer:

(b)  (x + 1 ≤ 1) ∩ (x + 1 ≥ 1) =  {x | x = 0}

Step-by-step explanation:

Here, the given expression is : {x | x = 0}

So, the ONLY element in the given set = {0}

Now, take each option and solve the given expression:

(a)  x + 1 < -1

Adding -1 BOTH sides, we get:

x + 1 -1 < -1  -1

or, x < - 2 ⇒ x = { -∞ , .... , -4,-3}

Also,   x + 1 < 1

Adding -1 BOTH sides, we get:

x + 1 -1 < 1  -1

or, x <0 ⇒ x = { -∞ , .... , -4,-3,-2,-1}

So, (x + 1 < -1) ∩ (x + 1 < 1) =  { -∞ , .... , -4,-3}∩ { -∞ , .... , -4,-3,-2,-1}  

=  { -∞ , .... , -4,-3}

⇒ (x + 1 < -1) ∩ (x + 1 < 1) ≠ {0}

Similarly, solving

(b) (x + 1 ≤ 1) ∩ (x + 1 ≥ 1)

(x + 1 ≤ 1) =  x≤ 0 =   { -∞ , .... , -4,-3,-2,-1, 0}

(x + 1 ≥ 1) =  x ≥ 0 =  {0,1,2,3,... ∞}

⇒ (x + 1 ≤ 1) ∩ (x + 1 ≥ 1) = {0}

(b)(x + 1 < 1) ∩ (x + 1 > 1)

(x + 1 < 1) =  x <  0 =   { -∞ , .... , -4,-3,-2,-1}

(x + 1 > 1) =  x  > 0 =  { 1,2,3,... ∞}

⇒ (x + 1 ≤ 1) ∩ (x + 1 ≥ 1) = Ф

Hence,  (x + 1 ≤ 1) ∩ (x + 1 ≥ 1) =  {x | x = 0}

8 0
3 years ago
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malfutka [58]

Answer:15

Step-by-step explanation:

3 0
2 years ago
What is the parent function of the following function?<br> f(x) = 3(5)*
Vlad [161]
I think it’s 15 f(x) 15
7 0
3 years ago
What is the slope of the line with an equation of 5x - 3y = -12
Hoochie [10]

Answer: m=\frac{5}{3} =1.67

Step-by-step explanation:

  1. Original equation:  5x-3y=-12
  2. Subtract 5x from both sides of the equation: -3y=-5x-12
  3. Divide both sides of the equation by -1: 3y=5x+12
  4. Divide both sides of the equation by 3 to get y on the left, leaving the equation in y=mx+b form: y=\frac{5}{3}x+4
  5. Evaluate. Slope is equal to m in this form, so the slope is m=\frac{5}{3}.

Hope this helps!

5 0
2 years ago
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