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3 years ago

What is 20x^2-40x-25

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

6 0

You have to know what x is to completely solve but you can simplify it to, 20x^-40x -23

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A car rental agency rents cars for $26.20 per day plus $0.22 per mile driven. If you rent the car for one day and your travel bu

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Answer: 600

Step-by-step explanation:

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3 years ago

Please help asap!:) Thank you!

finlep [7]

Answer:

(f + g)(3) = 9

Step-by-step explanation:

Given:

f(x) = x² + 1

g(x) = x - 4

Required:

(f + g)(3)

SOLUTION:

✔️Find f(3) by substituting x = 3 into f(x) = x² + 1:

f(3) = (3)² + 1 = 9 + 1

f(3) = 10

✔️Find g(3) by substituting x = 3 into g(x) = x - 4:

g(3) = 3 - 4

g(3) = -1

✔️Find (f + g)(3):

(f + g)(3) = f(3) + g(3)

= 10 + (-1)

= 10 - 1

(f + g)(3) = 9

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3 years ago

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There will be 100 hand shakes because you would do 10x10 which is 100

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3 years ago

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4 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

6 0

3 years ago