The question is incomplete as it does not have the options which are:
A) single-stranded complementary tails
B) blunt ends
C) poly-A sequences
D) 5' cap
E) interference
Answer:
A) single stranded complementary tails
Explanation:
Restriction endonuclease is the enzyme which cuts the DNA sequence in the internal sequence.
The endonuclease enzyme can cut the DNA sequence in a way that it can form the cuts with the single-stranded overhangs called sticky ends and without overhangs called blunt ends.
The sticky ends are produced when the enzyme makes cut at the single strand and then makes the cut at between the same base at the nitrogenous base. This type of asymmetrical cut forms the single-stranded overhangs which can form the complementary base pairs easily.
Thus, Option-A is correct.
Answer:
In the lysogenic cycle, the viral genome gets incorporated into the host genome and replicates with the host genome. In the lysogenic cycle, no proteins and enzymes of the virus are formed while in the lytic cycle protein of viral capsid form and new phages generate in the host cell.
So as the viral genome integrates into the host genome in the lysogenic cycle, therefore, it is difficult for any drug to differentially act on the viral genome. So there are great chances for drugs to target the host genome in the host cell.
But in virus that replicates through lytic cycle drugs can selectively act on viral enzyme and proteins. Therefore it is difficult to make a drug that affects lysogenic virus.
This is an example of thigmotropism I believe.