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2 years ago

3.2 is ten times as much as

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

3 0

Its ten times as much as 0.32

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The area of the region in the first quadrant between the graph of y = k*sin(x) and x-axis (where k > 0 ) on the closed interv

astraxan [27]

Note that $0\le k\sin x\le k$ in the given closed interval, so the area is exactly given by the definite integral

$\displaystyle\int_0^\pi k\sin x\,\mathrm dx$

(no absolute values needed!)

Integrating gives

$-k\cos x\bigg|_{x=0}^{x=\pi}=-k(\cos\pi-\cos0)=-k(-1-1)=2k$

8 0

2 years ago

50 POINTS!!!

san4es73 [151]

Step-by-step explanation:

Step 1: Determine an ordered pair

A solution of an equation just means that the point lies on the line. We can find any y-value when we plug in a specific x-value. For example, if we want to know what ordered pair lies at x=1, we just plug in y = -1/2(1) and solve for y which gives us -1/2. This gives us an ordered pair of (1, -1/2). We can continue to do this for any x value.

We can also reverse the order and plug in the y-value and get the x-value in order to accomplish the same goal but it's a bit harder.

Hope this helps!

6 0

1 year ago

Read 2 more answers

Consider angle θ in Quadrant II, where sinθ = 4/5 . What is the value of cosθ?

Kay [80]

Answer:

3/5

Step-by-step explanation:

sin theta=opposite/hypotenuse

4/5=opposite/hypotenuse

therefore opposite=4 and hypotenuse=5

for adjacent

using pythagoras theorem

a^2+b^2=c^2

opposite^2 + adjacent^2 =hypotenuse^2

4^2 + adjacent^2 =5^2

16 + adjacent^2 =25

adjacent^2 =25-16

adjacent = $\sqrt{9$

adjacent=3

cos theta=adjacent/hypotenuse

=3/5

therefore the value of cos theta is 3/5

8 0

2 years ago

If 5 students had to share 8 brownies how much would each student get

muminat

Each student would get 1.6 brownies

7 0

2 years ago

Read 2 more answers

What is the equation of the line that goes through the points (4,-1) and (2,3)?

Arturiano [62]

Answer:

y = -2x + 7

Explanation:

y = mx + b

m = slope

b = y-intercept

y = a given y coordinate

x = a corresponding x coordinate

First, we need to find the slope (m).

1) (4, -1)

2) (2/3)

m = slope = $\frac{y_2-y_1}{x_2-x_1}$ = $\frac{3-(-1)}{2-4}$ = $\frac{4}{-2}$ = -2

plug in the values to the equation y = mx + b

-1 = -2(4) + b

-1 = -8 + b

7 = b

now, we can substitute in m and b into the equation y = mx + b

y = -2x + 7

5 0

2 years ago