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shtirl [24]
3 years ago
12

A local car dealer is advertising a 2-year lease

Mathematics
1 answer:
MAVERICK [17]3 years ago
5 0

Answer:

c = 150m+3000

Step-by-step explanation:

So if 150 is the monthly payment and c is the total cost you'd be looking for c and 150 would be multiplied by m for how ever many months is takes to pay it off. You would then just add on the 3000 dollar deposit since its just a one time payment to start out with.

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41 out of 120 people chose their favourite fruit as bananas. Calculate the angle you would use for bananas on a pie chart
Sergio039 [100]
41/120= 0.3416
34% out of 100%
.34 multiplied by 360 degrees
122.4 degrees
5 0
3 years ago
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Solve for w k=2b-5w/3k
nlexa [21]
k = \frac{2b - 5w}{3k}
3k^{2} = 2b - 5w
3k^{2} + 5w = 2b
5w = 2b - 3k^{2}
w = \frac{2}{5}b - \frac{3}{5}k^{2}
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Choose the expression that represents the pattern of your sequence: 10, 20, 40, 80, ....
Angelina_Jolie [31]
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2 years ago
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For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
Given the function f(x)=(x-2)(x+3)(2x+3), which set includes all of the zeros for the polynomial?
Marrrta [24]

Answer:

{2, -3, -3/2}

Step-by-step explanation:

hi! we can set each of the binomials equal to 0 to find the zeros of this polynomial.

x-2=0

x=2

x+3=0

x=-3

2x+3=0

2x=-3

x=-3/2

5 0
3 years ago
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