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Agata [3.3K]
3 years ago
11

Which of the following represents the most accurate estimation of 5+4 5,10,15,20

Mathematics
2 answers:
mr_godi [17]3 years ago
7 0
If you rounded 4 up to 5 you would get 10 so 10 is the right answer
GalinKa [24]3 years ago
6 0
10 5+4 is 9 so it would be 10
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D is not right its a negative 8 so therefore it would be minus
Ilya [14]
I really dont understant your question. but you are right that negative 8 that it would be minus. <span>In </span>mathematics<span>, a </span>negative<span> number is a real number that is less than zero. </span>Negative<span> numbers represent opposites. If positive represents movement to the right, </span>negative<span> represents movement to the left.</span>
6 0
3 years ago
Help fast Fast Fast Fast
Ipatiy [6.2K]

Answer:

0,5

Step-by-step explanation:

4 0
2 years ago
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Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} &#10;&#10;2 =   e^{ \alpha t} &#10;&#10; \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
(8x-11)-(15-x)=1 dont know where to start with it​
schepotkina [342]

Answer:

<em>x</em><em> </em><em>=</em><em> </em><em>3</em>

Step-by-step explanation:

First open the brackets. While opening brackets, you've to be careful about signs. So when you open bracket of <em>(</em><em>1</em><em>5</em><em>-</em><em>x</em><em>)</em>, there's <em>negative</em> sign in front of it, so it makes the signs inside the brackets to change. Then you solve the it.

4 0
3 years ago
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The roots of the equation 2x^2+3x-5=0 are
GaryK [48]
I know it is -1 cause of the root of equation 

7 0
3 years ago
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