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2 years ago

How do your write a feaction with a denominator of 20 as a decimal?

Mathematics

1 answer:

Maslowich2 years ago

7 0

Answer:

Step-by-step explanation:

What is 20 as a decimal? To write 20 as a decimal you have to divide numerator by the denominator of the fraction. 20 is not a fraction so it is a decimal already. And finally we have: 20 as a decimal equals 20

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Which number when rounded to the nearest tenth is 43.6

Alex73 [517]

Answer:

Any number greater than 43.54 and less than 43.6 rounds to 43.6. So, 43.55, 43.56, 43.57, 43.58 and 43.59 all round up to 43.6.

8 0

2 years ago

A boy spent 3/8 of his money and had 15.00 left. How much did he spend?

geniusboy [140]

Answer: $25 spent

Step-by-step explanation: the boy spent $15/total.

15/total=3/8

Divide by common factor: $15/3=$5 (1/8 total money

$5x8=$40

$40-$15=$25 spent

6 0

1 year ago

What percent is 27.30 of 36.40 ?

Luden [163]

If you would like to know what percent is 27.30 of 36.40, you can calculate this using the following steps:

x% of 36.40 = 27.30
x/100 * 36.40 = 27.30
x/100 = 27.30/36.40
x = 27.30/36.40 * 100
x = 75

To check: 75% * 36.40 = 75/100 * 36.40 = 27.30

The correct result is 75%.

7 0

2 years ago

How is this solved using trig identities (sum/difference)?

GenaCL600 [577]

FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

$cos \beta = -\frac{1}{2} \sqrt{3}$

$tan \beta= \frac{1}{3} \sqrt{3}$

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
$sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )$
$sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )$
$sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})$

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
$cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )$
$cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )$
$cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )$

Find tan (α - β)
$tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha tan \beta }$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}$

Simplify the denominator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{1+(\frac{5\sqrt{3}}{24})}$
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the numerator
$tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }$
$tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }$

Simplify the fraction
$tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})$
$tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}$

7 0

2 years ago

I have four factors 3 of my factors are 1,2,and 6 what is my fourth factor

Naddik [55]

12
2 multiplied by 6 is 12 and so 1 multiplied by something is 12
Hope this helps.

7 0

3 years ago

Read 2 more answers

How do your write a feaction with a denominator of 20 as a decimal?​

How do your write a feaction with a denominator of 20 as a decimal?