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Bumek [7]
3 years ago
15

Find the magnitude of the vector:​

Mathematics
2 answers:
WITCHER [35]3 years ago
5 0

Answer:

Step-by-step explanation:

12345 [234]3 years ago
5 0

Answer:

\large\boxed{|\overrightarrow{CD}|=3\sqrt{61}}

Step-by-step explanation:

The formula of a magnitude of vector:

|\overrightarrow{AB}|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where

A(x_1,\ y_1),\ B(x_2,\ y_2)

We have:

C(10,\ 10),\ D(-8,\ -5)

Substitute:

|\overrightarrow{CD}|=\sqrt{(-8-10)^2+(-5-10)^2}\\\\|\overrightarrow{CD}|=\sqrt{(-18)^2+(-15)^2}\\\\|\overrightarrow{CD}|=\sqrt{324+225}\\\\|\overrightarrow{CD}|=\sqrt{549}\\\\|\overrightarrow{CD}|=\sqrt{(9)(61)}\\\\|\overrightarrow{CD}|=\sqrt{9}\cdot\sqrt{61}\\\\|\overrightarrow{CD}|=3\sqrt{61}

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---------------------------------------------------------------------------------------------------------------

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