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torisob [31]
4 years ago
14

Q1. Find y, if √12 - √147 + y√3 = 0

Mathematics
1 answer:
o-na [289]4 years ago
6 0

Answer:

Q1. y = 5 Q2.  (√2 - √3)/2

Step-by-step explanation:

Q1

√12 - √147 + y√3 = 0

Taking -√147 and √12 to the right hand side, we have

y√3 = √147 - √12

y√3 = √(3 × 49) - √(3 × 4)

y√3 = √3 × √49 - √3 × √4

y√3 = √3 × 7 - √3 × 2

y√3 = 7√3 - 2√3

y√3 = 5√3

Dividing both sides by √3, we have

y√3/√3 = 5√3/√3

y = 5

Q2

Sin45° - Cos30°

Since Sin45° = √2/2 and Cos 30° = √3/2

Substituting these values into the equation, we have

Sin45° - Cos30° = √2/2 - √3/2

Taking L.C.M of both factors, we have

Sin45° - Cos30° = (√2 - √3)/2

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Let the centre be O and the line with one end point at the centre and another at the chord CD touches the chord at S .

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