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Nataliya [291]
3 years ago
9

What is the circumference of a circle with a diameter of 10 feet? Use 3.14 as π

Mathematics
1 answer:
lianna [129]3 years ago
7 0

Answer:

31.4

Step-by-step explanation:

Happy holidays and have a great break!

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Answer:

b < = 65 <u><</u>

Step-by-step explanation:

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The temperature was -3° last night it is now -4° see what was the change in temperature was-3° C. It is -4° C. What was the chan
raketka [301]

Answer:

The temp got colder by -1

Step-by-step explanation:

The difference of -3 to -4

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Factor by Grouping 8x+8y+rx+ry<br> I do not understand this.
nadezda [96]
FACTORISATION IS BASICALLY FINDING LIKE-TERMS.
1. FIND THE HCF OF 8. HERE, THE HCF IS 8. ALSO, CHECK ALL THE LIKE-TERMS. LIKE-TERMS ARE OUTSIDE THE BRACKET AND UNLIKE TERMS ARE INSIDE.
2. ADD THE TERMS IN THE BRACKET AND THE TERMS OUTSIDE THE BRACKET FROM STEP 1.

8x + 8y + rx + ry
1. 8 (x + y) + r (x + y)
2. (x +y) (8+r)
8 0
3 years ago
Read 2 more answers
Is this perpendicular or parallel or neither y = -4/5x+3 And 4x -5y=-15
aleksley [76]
This would be perpendicular
6 0
3 years ago
Find the volume of the wedge-shaped region contained in the cylinder x2 + y2 = 49, bounded above by the plane z = x and below by
fiasKO [112]
\displaystyle\iiint_R\mathrm dV=\int_{y=-7}^{y=7}\int_{x=-\sqrt{49-y^2}}^{x=0}\int_{z=x}^{z=0}\mathrm dz\,\mathrm dx\,\mathrm dy

Converting to cylindrical coordinates, the integral is equivalent to

\displaystyle\iiint_R\mathrm dV=\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}\int_{z=r\cos\theta}^{z=0}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}-r^2\cos\theta\,\mathrm dr\,\mathrm d\theta
=-\displaystyle\left(\int_{\theta=\pi/2}^{3\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{r=0}^{r=7}r^2\,\mathrm dr\right)
=\dfrac{2\times7^3}3=\dfrac{686}3
4 0
3 years ago
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