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3 years ago

6^2-3^4 divided by 3^4

Mathematics

1 answer:

DerKrebs [107]3 years ago

6 0

Answer:

Step-by-step explanation:

6^2 - 3^4 / 3^4

Evaluate The Power

36 - 3^4 / 3^4

Any Expression Divided By Itself Is 1

36 -1

Subtract

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TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

borishaifa [10]

Answer:

A. It would be needed 20 packets to transmit 30,000 bytes of information.

B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

It would be needed 20 packets to transmit 30,000 bytes of information

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

6 0

3 years ago

10 POINTS PLEASE HELP

ICE Princess25 [194]

Volume= whl

W= 4 ft

H= 2ft

L= 5ft

Multiply all (40), then multiply by the three times it was full.

Answer: 120ft^3

4 0

3 years ago

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

3 0

3 years ago

Solve the following proportion problem for x: 14/3x=20/x-5

Butoxors [25]

14 20

---- = ----- cross multiply

3x x-5

14(x-5) = 3x (20)

14x - 70 = 60x

-14x -14x

-70 = 36x

/36 /36

-70/36 = x

-35/18 = x

5 0

3 years ago

Read 2 more answers

Four interior angles of a pentagon measure 156 degrees 72 degrees 98 degrees and 87 degrees. What is the measure of the final in

zepelin [54]

Answer:

127°

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180°(n - 2) ← n is the number of sides

here n = 5 ( Pentagon), hence

sum = 180° × 3 = 540°

To find the fifth angle subtract the sum of the 4 given angles from 540

angle = 540° - (156 + 72 + 98 + 87) = 540° - 413° = 127°

6 0

3 years ago