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Xelga [282]
3 years ago
13

The perimeter of a square is 20 ft. If you increase the length of the square by 2 feet and decrease the width by 1 foot, what is

the area, in square feet, of the new figure?
Mathematics
2 answers:
Mariulka [41]3 years ago
4 0
Technically, you can't do that because a square has equal side lengths
Tanzania [10]3 years ago
3 0
The perimeter of a square is found by just adding the lengths of the sides together. Since the square has four sides you just divide 20 by 4 to get 5 the length of each side. Then just add 2 to 5 to get the length of 7 and then subtract 1 from 5 to get 4 for the width. The new figure is going to be a rectangle so to find its area it's just width x length. 7 x 4 = 28 ft^2
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DerKrebs [107]

Answer:

m=-3

Step-by-step explanation:

m - 7 = -10

Ok so,

in order to get m by itself you just need to do the opposite of -7 which is +7 so you have to add 7 to both sides. On the left, both of the 7's cancel out and on the right -10 + 7 = -3. So, now it should look like this.

m=-3

To check you just need to plug in -3 into the question

Hope this helps! Have a good day

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Answer:

(2, 2) states x=2 and y=2

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The table represents a function.
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