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Xelga [282]
4 years ago
13

The perimeter of a square is 20 ft. If you increase the length of the square by 2 feet and decrease the width by 1 foot, what is

the area, in square feet, of the new figure?
Mathematics
2 answers:
Mariulka [41]4 years ago
4 0
Technically, you can't do that because a square has equal side lengths
Tanzania [10]4 years ago
3 0
The perimeter of a square is found by just adding the lengths of the sides together. Since the square has four sides you just divide 20 by 4 to get 5 the length of each side. Then just add 2 to 5 to get the length of 7 and then subtract 1 from 5 to get 4 for the width. The new figure is going to be a rectangle so to find its area it's just width x length. 7 x 4 = 28 ft^2
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Step-by-step explanation:

In order to find the value of y, we first have to note that the unlabeled angle in the larger triangle, y and the 78 degree angle create a straight line. The unlabeled angle is equal to 36 since it and the other two angles equal 180. So we take that 36, 78 and y and can set that equal to 180.

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