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Xelga [282]
3 years ago
13

The perimeter of a square is 20 ft. If you increase the length of the square by 2 feet and decrease the width by 1 foot, what is

the area, in square feet, of the new figure?
Mathematics
2 answers:
Mariulka [41]3 years ago
4 0
Technically, you can't do that because a square has equal side lengths
Tanzania [10]3 years ago
3 0
The perimeter of a square is found by just adding the lengths of the sides together. Since the square has four sides you just divide 20 by 4 to get 5 the length of each side. Then just add 2 to 5 to get the length of 7 and then subtract 1 from 5 to get 4 for the width. The new figure is going to be a rectangle so to find its area it's just width x length. 7 x 4 = 28 ft^2
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A parallelogram has a perimeter of 42 meters. Two sides are each 19.8 meters long. What is the length of the other two sides?
ValentinkaMS [17]
We first add both 19.8 by 19.8 and therefore, that would give us 39.6.

42 - 39.6 = 2.4.

2.4 ÷ 2 = 1.2

1.2 would be the length of each sides.
3 0
3 years ago
Read 2 more answers
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Novay_Z [31]

Answer:  3+\sqrt{2}

Step-by-step explanation:

Given the following expression shown in the picture:

\frac{7}{3-\sqrt{2} }

You need to use a process called "Ratinalization".

By definition, using Rationalization you can rewrite the expression in its simplest form so there is not Radicals in its denominator.

Then, in order to simplify the expression, you can follow the following steps:

<em>Step 1</em>. You need to multiply the numerator and the denominator of the fraction by  3+\sqrt{2}, which is the conjugate of the denominator  3-\sqrt{2}.

<em>Step 2</em>. Then you must apply the Distributive property in the numerator.

<em>Step 3</em>. You must apply the following property in the denominator:  (a+b)(a-b) = a^2 - b^2

Therefore, applying the procedure shown above, you get:

=\frac{(7)(3+\sqrt{2})}{(3-\sqrt{2})(3+\sqrt{2})}=\frac{21+7\sqrt{2}}{3^2-(\sqrt{2})^2}=\frac{21+7\sqrt{2}}{9-2}=\frac{21+7\sqrt{2}}{7}

<em>Step 4</em>.  You can observe that the expression can be simplified even more. Since:

 \frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}

You get:

\frac{21+7\sqrt{2}}{7}=\frac{21}{7}+\frac{7\sqrt{2}}{7}=3+\sqrt{2}

3 0
2 years ago
I’m actually confused.
-BARSIC- [3]
M^2 + n^2

Step 1:
Substitute in the numbers
-5^2 + 3^2

Step 2:
Square both numbers
25 + 9

Step 3:
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Answer is 34
8 0
2 years ago
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vredina [299]
149,400-44,000
=$105,400
8 0
3 years ago
2. what is the value of x? Show your work
Mademuasel [1]

Write a full questions to understand. You have wrote half questions only

7 0
1 year ago
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