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Xelga [282]
3 years ago
13

The perimeter of a square is 20 ft. If you increase the length of the square by 2 feet and decrease the width by 1 foot, what is

the area, in square feet, of the new figure?
Mathematics
2 answers:
Mariulka [41]3 years ago
4 0
Technically, you can't do that because a square has equal side lengths
Tanzania [10]3 years ago
3 0
The perimeter of a square is found by just adding the lengths of the sides together. Since the square has four sides you just divide 20 by 4 to get 5 the length of each side. Then just add 2 to 5 to get the length of 7 and then subtract 1 from 5 to get 4 for the width. The new figure is going to be a rectangle so to find its area it's just width x length. 7 x 4 = 28 ft^2
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Game consoles: A poll surveyed 341 video gamers, and 89 of them said that they prefer playing games on a console, rather than a
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Answer:

Step-by-step explanation:

Hello!

The objective is to test if the population proportion of gamers that prefer consoles is less than 28% as the manufacturer claims.

Of 341 surveyed players, 89 said that they prefer using a console.

The sample resulting sample proportion is p'= 89/341= 0.26

If the company claims is true then p<0.28, this will be the alternative hypothesis of the test.

H₀: p ≥ 0.28

H₁: p < 0.28

α: 0.05

To study the population proportion you have to use the approximation of the standard normal Z= \frac{p'-p}{\sqrt{\frac{p(1-p)}{n} } }≈N(0;1)

Z_{H_0}= \frac{0.26-0.28}{\sqrt{\frac{0.28*0.72}{341} } }= -0.82

This test is one-tailed left, i.e. that you'll reject the null hypothesis to small values of Z, and so is the p-value, you can obtain it looking under the standard normal distribution for the probability of obtaining at most -0.82:

P(Z≤-0.82)= 0.206

Using the p-value approach:

If p-value ≤ α, reject the null hypothesis

If p-value > α, don't reject the null hypothesis

The decision is to not reject the null hypothesis.

Then at a level of 5%, you can conclude that the population proportion of gamers that prefer playing on consoles is at least 28%.

I hope this helps!

4 0
3 years ago
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