130/105 in its simplest form
I wish you much success in your studies!!!!
I wish you much success in your studies!!!!
vera is measuring the size of a small hexagonal silver box that she owns. she places a standard 12 inch ruler alongside the box.
About how much long is one of the sides of the box?
1 answer:
I believe there is a corresponding figure to help answer this problem. See attached photo.
From the figure, we can see that there are 8 tick marks in an inch. The number of tick marks covering one side is about 5.5 tick marks. Therefore:
length = 5.5 tick marks * (1 inch / 8 tick marks)
length = 0.69 inches
You might be interested in
Answer: Option A
Step-by-step explanation:
Given the functions f(x) and g(x):
indicates that you need to subtract the function
and the function
.
Then:
Now, you need to dstribute the negative sign and then you have to add like terms. Then:
You can observe that this answer matches with the option A.
so the 5 gallons ones is 40% acid, how much acid solute is in it anyway? well just 40% of 5 or namely 0.4*5 = 2 gallons.
the 3 gallons one is 50%, likewise it has 0.50 * 3 = 1.5 gallons of acid solute in it.
Answer:
A)
B)
Step-by-step explanation:
AB has length a and is divided by points P and Q into AP , PQ , and QB , such that AP = 2PQ = 2QB
A) Therefore, AP = 2QB
QB = AP/2
The midpoint of QB = QB/2 = (AP/2)/2 = AP/4
AP = 2PQ, Therefore PQ = AP/2
Since the length of AB = a
AB = AP + PQ + QB = a
AP + AP/2 + AP/2 = a
AP + AP = a
2AP = a
AP = a/2
The distance between point A and the midpoint of segment QB = AP + PQ + QB/2 = AP + AP/2 + AP/4 = 7/4(AP)
But AP = a/2
Therefore The distance between point A and the midpoint of segment QB = 7/4(a/2)=
B)
the distance between the midpoints of segments AP and QB = AP/2 + PQ + QB/2 = AP/2 + AP/2 + AP/4 = 5/4(AP)
But AP = a/2
Therefore the distance between the midpoints of segments AP and QB = 5/4(AP) =