D midpoint of EC -----------------> FD parallel to AC and FD=AC/2=14/2=7
<span>2-EB=EA E midpoint of AB </span>
<span>DB=DC D midpoint BC ...............> ED=AC/2=2 </span>
<span>3-T midpoint of SR </span>
<span>U midpoint of QR ---------> TU = QS/2 </span>
<span>QS=2 TU = 4.4 </span>
<span>4- The same steps SR=2 UV=9 </span>
<span>5-N midpoint of KM </span>
<span>O midpoint of ML </span>
<span>* NO parallel to Kl</span>
Answer:
Step-by-step explanation:
We are given polynomial as
and it is divided by x=3 or x-3
we can use synthetic division
so, we got
Remainder =5
Quotient is
we can write as
Answer:
The distance between two points on a number line can be found by taking the <u>absolute value</u> of the <u>difference</u> of the coordinates.
Step-by-step explanation:
- Every point can be paired with a number on a number line
- The coordinate is the number associated with a point
- To find the distance between point A and B you subtract the coordinates in any order you like and take the absolute value.
