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soldi70 [24.7K]
3 years ago
14

A certain television is advertised as a 59-inch TV (the diagonal length). If the width of the TV is 49 inches, how tall is the T

V? Round to the nearest tenth of an inch.
please help I give brainiest
Mathematics
1 answer:
Serga [27]3 years ago
8 0

Answer: 32.9ft on delta math

Step-by-step explanation: none

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Help please this is also do very very soon thank you!!!
stepan [7]

Answer:

700

Step-by-step explanation:

100:2

???:14

14*100

=1400

1400/2

=700

3 0
3 years ago
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What's 2/3 divided by 1/4
svlad2 [7]

Answer:

8/3 or 2 and 2/3

Step-by-step explanation:

5 0
3 years ago
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Aminer started at 8 feet above sea level
3241004551 [841]

Answer:

-15 ft or 15 ft below sea level

Step-by-step explanation:

He started at +8 ft.

Then he went 23 ft down, that is -23 ft.

8 ft + (-23 ft) = 8 ft - 23 ft = -15 ft

Answer: -15 ft

4 0
3 years ago
What is an equation for a sine curve with amplitude 2, and period 4pi radians ?
Nezavi [6.7K]
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude  and  n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)

The correct answer is option D. y = 2 sin (θ/2)
===========================================

<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude  and  n = 2π/period
<span>amplitude = 5  , period = 2π/n = 2π/2 = π
</span>

The correct answer is option B. Period: pi radians: Amplitude:5

============================================================
3. tan (2π/3) = tan 120° = -√3 
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3

The correct answer is C. -sqrt3

=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3

The correct answer is <span>B.-sqrt3/3</span>
8 0
3 years ago
Help please. I need to finish this in five minutes!
e-lub [12.9K]

Answer:

i have no idea....

Step-by-step explanation:

but i hope someone helps :((  good luck:((

3 0
3 years ago
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