Only the third model shows parallel lines cut by a transversal.
We can solve this problem by using some properties that parallel lines cut by a transversal have. First of all, corresponding angles are congruent, and since the angles in figure 1 are corresponding but not congruent, that means that figure one is out.
In addition, in figure two, alternate exterior and interior angles of parallel lines intersected by a transversal are congruent, so since they are not in the picture, that means that this figure is also out.
Figure three is correct because since those are same side interior angles, they need to be supplementary for those to be two parallel lines intersected by a transversal. Since they do, in fact, add up to 180°, that means that the answer is figure three.
2^t =38
take the log of each side
log ( 2^t) = log (38)
the exponent gets multiplies
t log (2) = log (38)
divide by log 2
t = log(38)/log (2)
t≈5.2479
Yes all equilateral triangles are congruent. You can prove congruence with two congruent angles and all equilateral triangles will have 60º angles. Which is enough to prove similarity
Answer:
Step-by-step explanation:
Answer:
The smallest positive integer solution to the given system of congruences is 30.
Step-by-step explanation:
The given system of congruences is
where, m and n are positive integers.
It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as
Now, we can say that m>n because m and n are positive integers.
For n=1,
19 is not divisible by 5 so m is not an integer for n=1.
For n=2,
The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is
Therefore the smallest positive integer solution to the given system of congruences is 30.
