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3 years ago

Write the phrase as a rate in simplest form 260 inches in 15 seconds ?

Mathematics

2 answers:

iren [92.7K]3 years ago

8 0

Answer

17 (17.3 to be exact) inches per second would be the base or simplest rate

Explanation

the ratio of 260:15 is equivalent to 17:1

260/15=17.3 (I rounded to 17)

<em>hope this helps!</em>

<em>have a great day :)</em>

Lemur [1.5K]3 years ago

4 0

Answer:

52:3

Step-by-step explanation:

divide 260 by 5 and 15 by 5

260 divided by 5 = 53

15 divided by 5 = 3

260:15 = 52:3

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The following table shows how far a runner has gone in t minutes. Which of the following represents this information?

BigorU [14]

Answer:

The correct answer is B) d=250t.

Step-by-step explanation:

B is the correct answer because the total distance (d) equals 250 multiplied by the minutes (t) the runner has ran.

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2 years ago

The following wedge prism has a volume of

tiny-mole [99]

Answer:

The volume of the prism is 27 cubic inches.

Step-by-step explanation:

In order to calculate the volume of the given prism, we need to apply the correct formula. The volume of the wedge prism is given by the following formula:

$Volume = \frac{1}{2}*b*h*l$

Applying the data from the problem on the equation above, we have:

$Volume = \frac{1}{2}*6*4.5*2\\Volume = 6*4.5\\Volume = 27$

The volume of the prism is 27 cubic inches.

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3 years ago

Use the given endpoint R and midpoint M of line RS to find the coordinates of the other endpoins.

makvit [3.9K]

S(-6, 4)

If you plot on a simple graph you will find the other end point S there

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2 years ago

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snow_tiger [21]

the figure moved 7 to the right and 7 down

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2 years ago

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

7 0

3 years ago