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4 years ago

14

Very important part 2 ! Thank youuuuu !!!!!!!!!!

1 answer:

Sunny_sXe [5.5K]4 years ago

7 0

Answer: Neither linear nor exponential (choice B)

Through interpolation, a graphing calculator, or trial and error, you can find the function to be f(x) = 2x^2. This is a polynomial function. It is not linear as it graphs out a curved parabola. It's not exponential either since the exponent isn't a variable. This also can be considered a power function.

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10 points! Please help if able!

TEA [102]

The 30/60/90 right triangle is the biggest cliche in trig. We recall the sides come in ratio $1:\sqrt{3}:2$

$1:\sqrt{3}:2 = x:y:4\sqrt{2}$

First x:

$\dfrac x 1 = \dfrac{4 \sqrt{2}}{2}$

$x = 2 \sqrt 2$

Next y:

$\dfrac{y}{\sqrt{3}} =\dfrac{x}{1}$

$y= 2 \sqrt{2} \sqrt{3} = 2 \sqrt{6}$

Choice C

3 0

3 years ago

Please helpppp!!! Find the area of the irregular figure

OverLord2011 [107]

Answer:

The area of the figure is 143 sq in

Step-by-step explanation:

10 in * 7 in = 70 sq in

12 in * 4 in = 48 sq in

5 in * 5 in = 25 sq in

A = 70 sq in + 48 sq in + 25 sq in

A = 143 sq in

3 0

3 years ago

Roman55 [17]

Answer:

88m of fencing

Step-by-step explanation:

the cicumference of the garden is what we are looking out for,

and with the raduis .ie.14m

C=2πr

C=2•22/7•14

C=88m

8 0

3 years ago

Alan's dogs have a total of 24 legs (l). If each dog has 4 legs, which equation gives the number of dogs (d) that Alan has?

N76 [4]

Your answer would be A
He had 6 dogs
4x6d=24

3 0

3 years ago

Anton [14]

Answer:

Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider the ratio of the sides

$\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}$ ..............( 1 )

$\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}$ ..............( 2 )

$\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}$ ..............( 3 )

So By equation ( 1 ), ( 2 ) and ( 3 ) we get

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Now in Δ PQT and Δ QRS we have

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved

8 0

3 years ago