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Colt1911 [192]
3 years ago
10

Which of the following expressions represents the area of a trapezoid with bases of 3x and 5x and a height of 6x?

Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0
Trapezoid Area = (Base1 + Base2) (h/2)
so A = (3x + 5x )(6x/2)= 24x^2
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NEED HELP!! PLEASE PLEASE
Bezzdna [24]

Answer:

The answer is A

Step-by-step explanation:

hope this helps,

If you like my answer please give brainliest,

Happy Holidays!

6 0
3 years ago
Maths problem
Fudgin [204]

Answer:

250 x 3 = 750g

750g is your final answer

7 0
3 years ago
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Find the sum (the total measure) of the interior angles of an Octagon. Show all of your work
tatiyna
One way to do this is use the fact that the exterior angles of all polygons add up to 360 degrees
So an exterior angle of a regular octagon  = 360 / 8 = 45 degrees.
So each interior angle = 180 - 45 = 135 degrees

so total measure of all angles in octagon = 8 * 135 =  1080 degrees
4 0
3 years ago
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Lin sold 4 more shirts than Greg. Fran sold 3 times as many shirts as Lin. In total the three sold 51 shirts. Which represents t
Alex17521 [72]
 <span>Your Answer: D 

Why.... 

You can make equations out of the information 
Let L be Lin, G be Greg, and F be Fran 

L = 4 + G ---"Lin sold 4 more shirts than Greg" 
F = 3L ---"Fran sold 3 times as many shirts as Lin" 
F + G + L = 51 ---"In total the three sold 51 shirts" 

Use F + G + L = 51 
Substitute the equations in for F and L (because you need to know the G) like this.... 

(3L) + G + (4+G) = 51 

You still have a variable besides G in there... you can use the L= 4+G and substitute again so that there are only G's 

( 3(4+G) ) + G + (4+G) = 51 ---- SIMPLIFY :D 
( 12 + 3G ) + G + 4 + G = 51 
12 + 3G + G + 4 + G = 51 ---Combine like terms 
16 + 5G = 51 </span>
6 0
3 years ago
Help me please I literally don’t understand any of this. I know it’s easy too.
Ber [7]

Holigina, this is the solution:

Let's recall that √x = x ^(1/2)

Therefore,

√x√x = x ^(1/2 + 1/2) = x^1 (We sum the exponents of the same base)

The correct answer is C. 1

5 0
1 year ago
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