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2 years ago

Prac

Mathematics

1 answer:

PtichkaEL [24]2 years ago

8 0

Answer:

Yes a number with 3 digits is usually bigger than a number with 2 digits but sometimes if it is a decimal than the decimal can be bigger

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P=13 z=4

hram777 [196]

Answer:

you have more outfits than your friend

Step-by-step explanation:

you:

5*13=65outfits

friend:

4*9=36outfits

3 0

2 years ago

12=5x-13x-44. answer it in multi-step equations

fomenos

12=5x-13x-44

combine like terms

12 = -8x -44

add 44 to each side

12+44 = -8x

56= -8x

divide by -8 on each side

56/-8 = x

-7 =x

5 0

2 years ago

Read 2 more answers

Plz help ill give brainliest

kipiarov [429]

Answer:

243 in^3

Step-by-step explanation:

Cut into 2 rectangles

First one would be ..

12 x 8 = 96

second one would be

7 x 21 = 147

Add them together

147 + 96 = 243

7 0

2 years ago

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

2 years ago

For each question, each pair of triangles are similar but not drawn to scale. Calculate any lettered lengths.

Karolina [17]

Answer:

a. 20

b. 5

Step-by-step explanation:

The scale factor is 5 because 6×5=30

a. 4×5=20

b. 25÷5=5

8 0

1 year ago