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Sliva [168]
3 years ago
7

Jeff finds some bugs. He finds 10 fewer grasshoppers than crickets. He finds 5 fewer crickets than ladybugs. If Jeff finds 5 gra

sshoppers, how many ladybugs does Jeff find? How many circktets does he find? Write two equations to solve the problem.
Mathematics
1 answer:
AlexFokin [52]3 years ago
3 0
If Jeff has 5 grasshoppers, then he would have 15 crickets because x(grasshoppers)+10=y(crickets), and y(crickets)+5=z(ladybugs), which would leave Jeff with 20 ladybugs.
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aliina [53]

Answer:

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Step-by-step explanation:

If two lines have no solutions, that means that they are parallel. The slopes of two lines are the same if they are parallel. So n's slope is \frac{1}{2}. The y-intercept can be anything except -5, or +b. If two lines have infinitely many solutions, those two lines are exactly the same. So p is just m. If two lines have one and only one solution, that just means the slopes and y-intercepts are different. Since we don't know anything else about line r, we an't model an equation for it.

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3 years ago
Mr. Hughes gave 5/14
kow [346]

Answer:

His savings were of $4,200.

Step-by-step explanation:

Mr. Hughes gave 5/14 of his savings to his son, 2/3 of the remainder to his daughter, and the rest to his wife:

This means that the son and daughter amount is:

\frac{5}{14} + \frac{2}{3}(\frac{9}{14})

As \frac{9}{14} is the remained that his son did not get. So

\frac{5}{14} + \frac{2}{3}(\frac{9}{14}) = \frac{15}{42} + \frac{18}{42} = \frac{33}{42}

Fraction his wife got:

1 - \frac{33}{42} = \frac{42}{42} - \frac{33}{42} = \frac{9}{42}

If his wife got $900, what were his savings?

Total savings are x, wife got \frac{9}{42} of x. So

\frac{9x}{42} = 900

9x = 900*42

x = \frac{900*42}{9}

x = 100*42

x = 4200

His savings were of $4,200.

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2 years ago
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riadik2000 [5.3K]

Answer:

The two integers the square root of 62 falls between are 7, and 8.

Step-by-step explanation:

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alex41 [277]

Answer:

volume

Step-by-step explanation:

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