Answer:
Total percent of the room did she paint green = 60%
Step-by-step explanation:
Given - Cheryl painted her living room walls with two different colors. She painted part of the room yellow and another part green. If the surface area of the walls in her room is 720 ft² and she painted 288 ft² yellow.
To find - What percent of the room did she paint green ?
Proof -
Given that,
The surface area of the walls in her room = 720 ft²
Total area painted in yellow color = 288 ft²
So,
Total area painted in green color would be = 720 - 288 = 432 ft²
Now,
Let the total percent green color painted = x
So,
720 × x% = 432
⇒
⇒ x =
= 60
∴ we get
Total percent of the room did she paint green = 60%
Answer:
replace x with your answer and it should equal out
Step-by-step explanation:
This should be answer 3x^2-7y^2=5. by moving5 to the other side it becomes positive so, 0 becomes 5.
X=4
JK=17
JM=19
KM=17
This is the answer
The interquartile range is 4 to 5.5 because where the lines fall that is the different quartile range