The test organism ferments sucrose best under reduced oxygen conditions.
The sample was incubated less than 24 hours, which allowed for only limited fermentation.
The media was contaminated.
The organism is an obligate aerobe and therefore can only grow inside the Durham tube.
The media was prepared wrong.
The organism is limited in its ability to ferment sucrose. Since diffusion is restricted within the Durham tube and it contains only a small volume of media, it turned yellow first.
The test organism did not ferment sucrose.
1)The test organism ferments sucrose best under reduced oxygen conditions.
2)The sample was incubated less than 24 hours, which allowed for only limited fermentation.
3)The organism is limited in its ability to ferment sucrose. Since diffusion is restricted within the Durham tube and it contains only a small volume of media, it turned yellow first.
Answer:
4/3
Explanation:
For xy-plane coordinates, points are written as (x, y).
This question gives us two points and two line equations to solve this. Let's start with the first one.
Since p is the x value of the point and r is the y value of the point, we can place these values in our equation y = x + b as follows:
r = p + b
Now we do the same with our second point and line equation. We will substitute 2p for x and 5r for y in the equation y = 2x + b. So we get this:
5r = 2(2p) + b
5r = 4p + b
Since we have this two equations with the same two variables, now we can solve them using the elimination method.
In this case I eliminated b as it is constant in both equations. To do this I subtract the equations in order to cancel the b variable.
5r = 4p + b
r = p + b
_______ -
5r - r = 4p + b - p - b
4r = 3p
4/3 = p/r
