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andriy [413]
3 years ago
8

What is the algebraic expression for the difference of 10-u

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

The algebraic expression for the difference of 10 and u is 10-u.

Step-by-step explanation:

We need to find an algebraic expression for the difference of 10 and u.

If a and b are two real number, then the algebraic expression for the difference of a and b is

Algebraic Expression = a - b

In the given problem a=10 and b=u. The difference of 10 and u is defined by the expression

Algebraic Expression = 10 - u

Therefore the algebraic expression for the difference of 10 and u is 10-u.

puteri [66]3 years ago
4 0
I'm pretty sure that you answered it correctly. 10-U

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2/9 of the people on the restaurant are adults. If there are 95 more children than adults, how many children are there in the re
yan [13]
A: Adults
C:children
P: people
A= 2/9 P
C= A+95
P= A+C
= 2/9P + 2/9P+95
= 4/9 P+95, add -4/9P for both sides (same terms, same sides:))
P- 4/9P= 95
5/9P= 95
P= 171 people in the restaurant
Adult= 2/9*171= 38 Adults
Children= 38+95= 133 children
7 0
3 years ago
Une particule se déplace le long de la courbe y = 2x 2 – x + 3 et son abscisse est donnée par x = t 3 – 2t. Trouver la vitesse d
Mars2501 [29]
2*2=4 first you multiply  
4-1=3 then subtract  
3+3=6 now you add and that is your answer =6
7 0
3 years ago
2. Patients arrive at a hospital accident and emergency department at random follow a
mina [271]

Answer:

a )i) 0.117

ii)0.4126

b)0.7769

6 0
2 years ago
According to an article in Newsweek, the natural ratio of girls to boys is 100:105. In China, the birth ratio is 100:114 (46.7%
mojhsa [17]

Answer:

z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154  

p_v =2*P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=63 represent the number of girls born

\hat p=\frac{63}{150}=0.42 estimated proportion of girls born

p_o=0.467 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion if girls is 0.467.:  

Null hypothesis:p=0.467  

Alternative hypothesis:p \neq 0.467  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

3 0
3 years ago
Reduced form of 2ab^2-a^2 b^2/5
Ket [755]

Answer:

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

                 =\frac{2ab^2\cdot \:5-a^2b^2}{5}

                 =\frac{10ab^2-a^2b^2}{5}

Thus,

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

7 0
3 years ago
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