False. Some words like point, line and plane are not defined.
Answer:
Step-by-step explanation:
Parallel to y=2÷3x+6
Passes through (6,7)
slope is (2/3)
Solve for when y is 7 and x is 6.
take out the + 6 at the end because it doesnt change the slope. replace with b. (y=mx+b)
replace y and x.
7 = (2/3)(6)+b
solve for b and then put it back into the equatio and make 6 and 7 into x and y again.
Answer:
6(11+6)
Step-by-step explanation:
Greatest common factor of 66 and 36 = 6
66+36 = 6*11 + 6*6 = 6(11+6)
Answer:
25.5 mph
Step-by-step explanation:
So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed
So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15
y=2(0.25)+40
y=0.5+40
y=40.5
So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed
40.5 - 15 = 25.5
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2
