Using equation of motion.
S = ut + (1/2)gt²
Where S = Height, t = time, g = acceleration due to gravity = 9.8 m/s²
time, t = 8 seconds
Since it was dropped from height, initial velocity, u = 0
S = 0*t + (1/2)gt²
S = (1/2)gt²
S = (1/2)*9.8*8² = 4.9 * 8 * 8 = 313.6
Therefore the ledge is 313.6 m tall.
The cost will be 9 for 1 pencial
Answer:
p is approximately equal to 1.125, -1.925
Step-by-step explanation:
We can solve this first by expanding, giving us a quadratic equation in the usual ax² + bx + c format, then solving that for p:
(4p - 4)(13p + 27) = 0
52p² + 108p - 52p - 108 = 0
52p² + 52p - 108 = 0
13p² + 13p - 27 = 0
13p² + 13p = 27
p² + p = 27 / 13
p² + p + 1/4 = 27/13 + 1/4
(p + 1/2)² = 108 / 52 + 13 / 52
(p + 1/2)² = 121 / 52
p + 1/2 = ± √(121 / 52)
p = -1/2 ± 11√(1/13) / 2
At that point we can simply plug those numbers into a calculator and solve it:
p ≈ 1.125, -1.925
Answer:
7:56 A.M.
Step-by-step explanation:
1 hour and 59 mins = 119 mins
119+18 = 137
137/60 = 2 r 17
(10 - 2 = 8) - 17/60
Therefore they left at 7:56 A.M.
Answer:
Start from the origin(0,0) since there is no y-intercept. Go up 4 and over 1.
Step-by-step explanation: