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Sedaia [141]
3 years ago
5

Jesse owes $8,473 on a credit card with a 21.5% interest rate. What is the monthly payment he should make to pay off this debt i

n 12 months, assuming he does not charge any more purchases with the card?
1)

$706.08


2)

$164.57


3)

$790.99


4)

$2,016.54

Mathematics
1 answer:
kakasveta [241]3 years ago
3 0
You can use an online credit card calculator in computing the monthly payment. Refer to the attachment for the answer and graph. The given are the following: balance - 8,473; interest rate - 21.5%; months - 12. The answer is the third option - you'll need to pay <span>$790.99 every month for 12 months.</span>

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A Norman window has a length of 3 ft and width of 4 ft find the area of the rectangular piece of the glass
KengaRu [80]

Area= Length * Width

3*4= 12

Answer: 12ft^2

7 0
3 years ago
There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an
vesna_86 [32]

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

C =100 -50\\C= 50\ students

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

D =110 -50\\C= 60\ students

The number of students that have taken a course in either calculus or discrete mathematics is:

E = C+D = 50+60\\E= 110\ students

7 0
3 years ago
4-13 Students in a management science class have just re- ceived their grades on the first test. The instructor has provided inf
inessss [21]

Answer:

a) y = 0.74x + 18.99; b) 80; c) r = 0.92, r² = 0.85; r² tells us that 85% of the variance in the dependent variable, the final average, is predictable from the independent variable, the first test score.

Step-by-step explanation:

For part a,

We first plot the data using a graphing calculator.  We then run a linear regression on the data.

In the form y = ax + b, we get an a value that rounds to 0.74 and a b value that rounds to 18.99.  This gives us the equation

y = 0.74x + 18.99.

For part b,

To find the final average of a student who made an 83 on the first test, we substitute 83 in place of x in our regression equation:

y = 0.74(83) + 18.99

y = 61.42 + 18.99 = 80.41

Rounded to the nearest percent, this is 80.

For part c,

The value of r is 0.92.  This tells us that the line is a 92% fit for the data.

The value of r² is 0.85.  This is the coefficient of determination; it tells us how much of the dependent variable can be predicted from the independent variable.

3 0
3 years ago
Select the correct answer from each drop-down menu. ∆ABC has vertices at A(12, 8), B(4, 8), and C(4, 14). ∆XYZ has vertices at X
lakkis [162]

Answer: The correct option for blank 1 is option B and the correct option for blank 2 is option C.

Explanation:

It is given that ∆ABC has vertices at A(12, 8), B(4, 8), and C(4, 14). ∆XYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14). ∆MNO has vertices at M(4, 16), N(4, 8), and O(-2, 8). ∆JKL has vertices at J(14, -2), K(12, 2), and L(20, 4).

Plot these vertices on a coordinate plane and draw the triangles as shown below figure.

Two triangles are congruent if the both triangle have same corresponding sides and same angles.

From the figure it is noticed that

AB=MN=8

BC=NO=6

\angle B=\angle N

By SAS rule ∆ABC and ∆MNO are congruent.

So, the correct option for blank 1 is B.

From the It is clearly noticed the when we rotate the triangle ∆ABC 90^{\circ} counterclockwise along point B, we get ∆MNO.

So, the correct option for blank 2 is C.

3 0
3 years ago
Can you please solve the following equation?
AlladinOne [14]

Answer:

x=3.903

Step-by-step explanation:

2^{x-3}.5^{x-1}=200\\2^x.2^{-3}.5^x.5^{-1}=200\\\frac{2^x}{2^3}.\frac{5^x}{5^1}=200\\\frac{2^x.5^x}{2^3.5}=200\\\frac{(2.5)^x}{8.5}=200\\10^x=200 \times 40\\10^x=8000\\log 10^x=log8000\\x=\frac {log8000}{log10}=log8000=log 8\times log1000=log 8+log 1000=log2^3+log10^3=3log2+3log10=3log2+3 \approx0.903+3 \approx3.903

7 0
3 years ago
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