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Stolb23 [73]
3 years ago
5

Find a cubic function with the given zeros. 3, -4, 7

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0
\bf \begin{cases}
x=3\implies &x-3=0\\
x=-4\implies &x+4=0\\
x=7\implies &x-7=0
\end{cases}
\\\\\\
(x-3)(x+4)(x-7)=\stackrel{y}{0}\implies \stackrel{FOIL}{(x^2+x-12)}(x-7)=y
\\\\\\
x^3+x^2-12x-7x^2-7x+84=y\implies x^3-6x^2-19x+84=y
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