Answer:
B. , just did the assignment
Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Answer:
Y= 5/6x+5
Step-by-step explanation:
Okay same as before
the slope is rise over run
The rise is 5
The run is 6
So 5/6
And since ts rising from left to right its positive
The y-intercept which is the first point the line touches the Y axis is 5
So y=5/6x+5
Easy all you have to do is do 3 + 9 equals 20 which we all know that because we're in high school haha anyways back to what you do 3 + 9 which equals 12 we do we have to flip it around so if you sent it around it will be 12 equals 9 + 3 no I just read it so it would be 12 plus 9 which equals 3 which we know that so you have to flip the device which is going to eat with 3 or 12 - 9 which is going to eat you 3 that's what I'm going to put with that
